8x^2+2x-37=0

Solution for 8x^2+2x-37=0 equation:

8x^2+2x-37=0

a = 8; b = 2; c = -37;
Δ = b2-4ac
Δ = 22-4·8·(-37)
Δ = 1188
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1188}=\sqrt{36*33}=\sqrt{36}*\sqrt{33}=6\sqrt{33}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-6\sqrt{33}}{2*8}=\frac{-2-6\sqrt{33}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+6\sqrt{33}}{2*8}=\frac{-2+6\sqrt{33}}{16}
$